If 27^x = 3^2x+3, then find x.
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Answered by
0
So, 27^x= 3^3x
Now, as we know that bases are equal we form equation with the powers of the digits and further forming equation with the powers we get the answer 1.
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Answered by
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See 27 can be written as 3^3
So we get 3^3x= 3^2x+3^1
3^3x_3^1= 3^2x
3^3x/3^2x-3^1/3^2x=1
3^x-3^1-2x=1
3^x= 3^1-2x
Bases are same so
X= 1-2x
So x+2x= 1
So 3x= 1
So x= 1/3
So we get 3^3x= 3^2x+3^1
3^3x_3^1= 3^2x
3^3x/3^2x-3^1/3^2x=1
3^x-3^1-2x=1
3^x= 3^1-2x
Bases are same so
X= 1-2x
So x+2x= 1
So 3x= 1
So x= 1/3
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