Question

If the sum of three consecutive even integers is 36. What will be the smallest number?

Answer 1

Answer:

Let the consecutive integers be N

so other consecutive integer would be N+1 and N+2.

so,if we add all three integers we get 36.

Solution:

if we add

N+N+1+N+2 we get 36.

so in equation it will be

N+N+1+N+2=36. ( now we will solve L.H.S)

2N+1+N+2=36

3N+1+2=36

3N+3=36. ( now 3 will move towards 36)

3N=36-3. ( 3 was positive but after moving another side of =

singn it became -3)

3N=33

N=33÷3

N= 11.

so consecutive integer would be 11,12and13 .

hope this may help you.

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