if 278/2^3m has a terminating decimal expansion and m is a positive integer such that 2<m<9.Then find the value of m , pls answer fast
wvaish:
For a fraction to be terminating,it should either have only 2 or only 5 or both 2and 5 as the prime factors of the denominator. But here even 3is also present in the denominator. So it cannot be a terminating decimal.
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Answered by
161
if27823 m has terminating decimal expansion and m is a positive integer .
We know if any fraction have terminating decimal expansion then have denominator in form of
2a×5b
So,m = 5 ,
As m lies between 2 and 9 ( 2 < m< 9 ).
We know if any fraction have terminating decimal expansion then have denominator in form of
2a×5b
So,m = 5 ,
As m lies between 2 and 9 ( 2 < m< 9 ).
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Answered by
1
Answer: 5
Explanation: 278/2^3m has a terminating decimal expansion
Here m is a positive integer
If any fraction has terminating decimal expension then we can write denominator as 2a × 5b so here m = 5
position of 5 is between 2 and 9
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