Math, asked by dipikadas91, 12 days ago

if 28 cows cost as much as 10 horses, how many horses can be exchanged for 126 cows?​

Answers

Answered by studyillogical
1

Answer:

45 Horses

Step-by-step explanation:

28 Cows = 10 Horses

Cows : Horses = 10 : 28 = 5 : 14

(126/14) × 5 = 45

45 Horses can be exchanged.

Please Brainliest my answer

Answered by hima63718
1
Given,
28 cows = 10 horses
1 cow = 10/28 horses

(By simple unitary method)
126*1 = (10*126)/28
126 = (10*126)/28
126 = 1260/28
126 = 45

You need 45 horses to exchange with 126 cows

Hope it will help you.
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