if 28 cows cost as much as 10 horses, how many horses can be exchanged for 126 cows?
Answers
Answered by
1
Answer:
45 Horses
Step-by-step explanation:
28 Cows = 10 Horses
Cows : Horses = 10 : 28 = 5 : 14
(126/14) × 5 = 45
45 Horses can be exchanged.
Please Brainliest my answer
Answered by
1
Given,
28 cows = 10 horses
1 cow = 10/28 horses
(By simple unitary method)
126*1 = (10*126)/28
126 = (10*126)/28
126 = 1260/28
126 = 45
You need 45 horses to exchange with 126 cows
Hope it will help you.
28 cows = 10 horses
1 cow = 10/28 horses
(By simple unitary method)
126*1 = (10*126)/28
126 = (10*126)/28
126 = 1260/28
126 = 45
You need 45 horses to exchange with 126 cows
Hope it will help you.
Similar questions