If 29.3 g of CH₃OH (MM = 32.04 g/mol) are dissolved in 500.0 mL of solvent, what is the concentration of CH₃OH in the resulting solution?
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Answer:
Given,
Mass of CH3OH = 29.3 g
Molar mass of CH3OH = 32.04 g/mol
Volume of solution = 500.0 mL = 0.5 L (1 mL = 0.001 L)
The moles of CH3OH can be calculated as:
moles= 29.3\32.04 =0.914
concentration= 0.914/0.5 = 1.828
Explanation:
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