Question

If 29 sin theta= 21 find cos^2 theta- sin^2 theta/ 1-2 sin^2 theta

Answer 1

Simplify:

Step-by-step explanation:

$\ Given \ value: \\\\\ 29 \sin \theta =21\\\\\sin \theta \ =\frac{21}{29} \\\\\ Find:\\\\\frac{\cos^2\theta -\sin^2\theta}{1-2\sin^2\theta} \\\\\ Solution:\\\\\rightarrow \frac{1- \sin^2\theta -\sin^2\theta}{1-2\sin^2\theta} \\\\\rightarrow \frac{1- 2\sin^2\theta}{1-2\sin^2\theta} \\\\\rightarrow 1$

$\ OR \ \ \ \ \ \\\\\sin \theta =\frac{21}{29}\\\\\ so, \cos \theta= \frac{20}{29}\\\\\ put \ the \ value \ in \ given \ equation \ we \ get \ the \ value \ is \ = \ 1$

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