Math, asked by Akbarali111, 1 year ago

if 2a-3b =3 and ab =2, find the value of 8a3-27b3

Answers

Answered by Swarup1998
27
Solution :

Now,

8 {a}^{3} - 27 {b}^{3} \\ = {(2a - 3b)}^{3} + (3 \times 2a \times 3b\times(2a - 3b)) \\ = (2a - 3b)^{3} + 18ab(2a - 3b) \\ = {3}^{ 3} + 18 \times 2 \times 3 \\ = 27 + 108 \\ = 135

[Ans.]

Akbarali111: if you multiply 12ab and 2a how will you get 18
Akbarali111: can u please explain that step
Akbarali111: that one:3^3 +18 *2*3
Swarup1998: the vaues are given in the question.
Swarup1998: see the answer again
Swarup1998: i have edited it
Akbarali111: ohh thank u so much
Akbarali111: which formula did u use
Swarup1998: a^3 - b^3 = (a - b)^3 + 3ab(a - b)
Akbarali111: ok
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