Question

If (2a-b)²+(b-2c)²=0, then (a+c):b=?​


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Answer 1

Step-by-step explanation:

(2a-b)²+(b-2c)²=0

$(2a-b)²+(b-2c)²=0 \\ \\ 4 {a}^{2} - 4 ab + {b}^{2} + {b}^{2} - \:4 bc + 4 {c}^{2} \\ 4 {a}^{2} - 4 ab + 2 {b}^{2} - 4bc + 4 {c}^{2} \\ \\ \\ 2(2 {a}^{2} - 2ab + {b}^{2} - 2bc + 2 {c}^{2} )$