If 2and-3 are the zeros of the polynomial x2+(a+1)x+b. Thn find the value of a and b
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6 + 2a + b = 6-3a+ b
6+2a+b -6+3a-b = 0
2a+ 3a = 5 a
a= 1/5
sub in second equation
6 -3(1/5)+ b = 6- 3/5+ b
= -27/5
hope it helps you......
snighda43:
is it right...ans are u sure
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