Question

If (2cos 2A -1)(tan3A-1)=0;find all possinle values of angle A.​

Answer 1

Here is your answer mate ...

Answer 2

Step-by-step explanation:

Given, (2cos2A−1)(tan3A−1)=0

Either 2cos2A−1=0 or tan3A−1=0

cos2A= 1/2

or tan3A=1

cos2A=cos60°

or tan3A=tan45°

2A=60

or 3A=45

A=30

or A=15

A=30 , 15

Hence, value of can be 30° and 15°