Physics, asked by rainyroy362, 1 month ago

If 2J work was required to move 2 coulomb electric charge from A to B. Then what is the
potential difference between A and B

Answers

Answered by aitijhyamondal
2

Explanation:

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Answered by Laraleorapathi
1

Explanation:

The total work done = energy transferred.

so, we might see the equation energy = voltage x charge, E = V * Q, written as,

work = voltage x charge, W = V * Q.

In this case, the charge is 4 mC, that is, 0.004 C and work done is 2 J.

Therefore, V=W/Q = 2/0.004 = 500 V.

Hence, the potential difference between two points if 2 J of work must be done to move a 4 mC charge from one point to another is 500 V.

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