Question

If 2k+1, 13, 5k-3 are three consecutive terms of AP then k=?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

★ Answer

2k+1, 13, 5k-3 are three consecutive terms of an Airthemetic progression series .

common difference of series

13-(2k+1) = 5k-3 -13

13-2k-1 = 5k-16

12+16 = 5k+2k

28 = 7k

k = 28/7

k = 4

solution:

k = 4

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