Question

If 2k+1, 13, 5k–3 are three consecutive terms of AP, then k = .....,select a proper option (a), (b), (c) or (d) from given options so that the statement becomes correct.(All the problems refer to A.P.)
(a) 17
(b) 13
(c) 4
(d) 9

Answer 1

Answer:

Step-by-step explanation:

Consecutive terms in Ap have a common difference,hence:-

13-(2k+1)=5k-3-13

29=5k+2k+1

7k=28

k=4

Hence, option C is the answer.

Hope you understood

Answer 2

Answer:

Option C is your answer

Step-by-step explanation:

Consecutive term in Ap have a common difference, hence:-

13- ( 2k + 1) = 5k - 3- 13

29 = 5k+ 2k+ 1

7k= 28

K = 4

Hope u understand✨✨