Math, asked by ameeribcd, 3 months ago

If (2k+1),(4k+3) and (8k+1) are three consecutive terms of an AP.Find the value of k and 18th term of the sequence.​

Answers

Answered by amitnrw
11

Given : (2k+1),(4k+3) and (8k+1) are three consecutive terms of an AP

To Find :  value of k

Solution:

(2k+1),(4k+3) and (8k+1) are three consecutive terms of an AP

=> (2k + 1) + (8k + 1)  = 2(4k + 3)

=> 2k + 1 + 8k + 1 = 8k  + 6

=> 2k + 2 = 6

=> 2k = 4

=> k = 2

Value of k = 2

As we do not know 1st term we can not find 18 th term

Assuming (2k+1),(4k+3) and (8k+1) are first three terms

Then  5 , 11 , 17  

a = 5

d = 6

18th term = 5  + ( 18 - 1) * 6

= 5 + 17 * 6

= 5 + 102

= 107

18th term = 107

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Answered by chethan1398
1

Step-by-step explanation:

see got u Ans ...check plz

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