Question

if 2k+1, b , 3k +1 are in an AP then find the value of k​

Answer 1

Answer:

2k+1,b,3k+1 are in AP

b-2k+1=3k+1-b

b+b-2k-3k+1-1=0

2b-5k+0=0

2b-5k=0

-5k=-2b

k=-2b/-5

k=2b/5