Question

If (2K-3,K2)is a solution of the equation 2x3y15=0,then find the value of K​

Answer 1

2x3y15=0 ………Equation 1

as (2K-3,K2)is a solution of the Equation 1.

using (2k-3) in position of x & k² in position of y we get ;

2(2k-3)k² ×15 =0

(2k-3)k²= 0

so , k= 0,0, 3/2