If 2k ,(4k-3) and (4k+4) are in Ap find tvalue of k
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Answered by
2
if these are in AP.
then 2b=a+c
2(4k–3)=2k + (4k+4)
hence k=5
hope it helped!
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then 2b=a+c
2(4k–3)=2k + (4k+4)
hence k=5
hope it helped!
mark as brainliest
Answered by
2
2b = a+ c
A=2k
B=4k-3
C=4k+4
2(4k-3)= 2k+4k+4
8k-6=6k+4
10 = 2k
Value of k= 5
A=2k
B=4k-3
C=4k+4
2(4k-3)= 2k+4k+4
8k-6=6k+4
10 = 2k
Value of k= 5
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Both methods are correct
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