if (2p-3q)2=0 then 6p/9q=?
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Solution :-
→ (2p - 3q)² = 0
→ (2p - 3q) * (2p - 3q) = 0
taking them equal to zero now,
→ (2p - 3q) = 0
taking 3q to RHS side and changing the sign,
→ 2p = 3q
multiply by 3 both sides,
→ 3(2p) = 3(3q)
→ 6p = 9q ----- Eqn.(1)
then,
→ (6p/9q)
from Eqn.(1),
→ (9q/9q)
→ 1 (Ans.)
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if p=4, q= -3 and r=2, find the value of : p³+q³-r³-3pqr
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