Question

If 2s =a+b+c find (s+a) 3-(s-b)3-3(s+a) (s-b) (a+b)

Answer 1

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Answer 2

$(s+a)^3-(s-b)^3-3(s+a)(s-b)(a+b)=(a+b)^3$

Step-by-step explanation:

Given : 2s =a+b+c

To find : $(s+a)^3-(s-b)^3-3(s+a)(s-b)(a+b)$ ?

Solution :

The expression,  $(s+a)^3-(s-b)^3-3(s+a)(s-b)(a+b)$

Using algebraic identity,

$(x-y)^3=x^3-y^3-3xy(x-y)$

In the expression, $x=s+a$ and $y=s-b$

So, we can re-write expression as,

$(s+a)^3-(s-b)^3-3(s+a)(s-b)(a+b)=(s+a-(s-b))^3$

$(s+a)^3-(s-b)^3-3(s+a)(s-b)(a+b)=(s+a-s+b)^3$

$(s+a)^3-(s-b)^3-3(s+a)(s-b)(a+b)=(a+b)^3$

#Learn more

If a + b + c = 2s then the value of (s - a)² + (s + b)² + (s - c)² will be ?

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