Give me 5 difficult questions with answers about Fatorisation of exponents. It should not be easy.
Best one will be marked as Brainliest.
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1) (a^3)^2 * (b^2)^3 * (a^3) * (b^2) / (a^12) * (b^12) * (a^2) * (b^3) = ?
2) (√a³) * (∛b²) * ((√c)²)³ / (∛a) * (√b) = ?
3) ((((a²)³)^4)^5)^6 = ?
4) (√a(√a(√a(√a......) = ?
5) (∛a(∛a(∛a(∛a........) = ?
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2) (√a³) * (∛b²) * ((√c)²)³ / (∛a) * (√b) = ?
3) ((((a²)³)^4)^5)^6 = ?
4) (√a(√a(√a(√a......) = ?
5) (∛a(∛a(∛a(∛a........) = ?
HERE IS WHAT YOU ASKED.
HOPE IT HELPS.
Toshu25:
[] what it means?
Answered by
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No. 1
=x^3×(x^8)^2-x×(x^8)^2+x^2×(x^8)+(x^8)+1
let x^8 be @
=x^3×@^2-x×@^2+x^2×@+@+1
=x@^2(x^2-1)+@(x^2+1)+1
=x@^2(x-1)(x+1)+@{x(x-1)+(x+1)}+1
=x@^2(x-1)(x+1)+x@(x-1)+@(x+1)+1
=x@(x-1){@(x+1)+1}+1{@(x+1)+1}
=(@x+@+1){x@(x-1)+1}
=(x^9+x^8+1){x^8(x^2-x)+1)
=(x^9+x^8+1)(x^10-x^9+1)
No.2
=(bc+ab+c^2+ca)(a+b)+abc
=abc+b^2c+a^2b+ab^2+c^2a+bc^2+a^2c+abc+abc
=(a^2b+a^2c+abc)+(b^2c+b^2a+abc)+(c^2a+c^2b+abc)+(c^2a+c^2b+abc)
=a(ab+ac+bc)+b(bc+ab+ac)+c(ca+bc+ab)
=(ab+bc+ca)(a+b+c)
Sorry for just two answer but this two are quite tough.
Hope it helped.
=x^3×(x^8)^2-x×(x^8)^2+x^2×(x^8)+(x^8)+1
let x^8 be @
=x^3×@^2-x×@^2+x^2×@+@+1
=x@^2(x^2-1)+@(x^2+1)+1
=x@^2(x-1)(x+1)+@{x(x-1)+(x+1)}+1
=x@^2(x-1)(x+1)+x@(x-1)+@(x+1)+1
=x@(x-1){@(x+1)+1}+1{@(x+1)+1}
=(@x+@+1){x@(x-1)+1}
=(x^9+x^8+1){x^8(x^2-x)+1)
=(x^9+x^8+1)(x^10-x^9+1)
No.2
=(bc+ab+c^2+ca)(a+b)+abc
=abc+b^2c+a^2b+ab^2+c^2a+bc^2+a^2c+abc+abc
=(a^2b+a^2c+abc)+(b^2c+b^2a+abc)+(c^2a+c^2b+abc)+(c^2a+c^2b+abc)
=a(ab+ac+bc)+b(bc+ab+ac)+c(ca+bc+ab)
=(ab+bc+ca)(a+b+c)
Sorry for just two answer but this two are quite tough.
Hope it helped.
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