Question

If 2sin 2∅≈√2,where 0°≤∅≤90°, find ∅
​

Answer 1

Answer:

θ = 22.5°

Step-by-step explanation:

We know that,

0° < θ < 90°

also, 2 × Sin(2θ) = √2

Sin(2θ) = √2/2

we know that, 2 = √2 × √2

Sin(2θ) = √2/(√2 × √2)

Sin(2θ) = 1/√2

But we know that, Sin(45°) = 1/√2

Then,

Sin(45°) = Sin(2θ)

so,

2θ = 45°

θ = 45/2 = 22.5°

Hope it helped and you understood it........All the best