Question

If (2t+1) is the factor of the polynomial p(t)=t^3+4t^2-t-1 then find the value of p(-1/2)

Pls help anyone.........

Answer 1

Answer:

3/8

Step-by-step explanation:

p(t) =t^3+4t^2-t-1

therefore,

p(-1/2)=(-1/2)^3+4(-1/2)^2-(-1/2)-1

=(-1/8)+4(1/4)+1/2-1

=(-1/8)+(4/4)+1/2-1

=(-1/8)+(1/2)

LCM=8

=(-1/8)+(4/8)

=3/8

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