Question

If 2x+1 is a factor of (3k+2)xcube+(k-1) find the value of k

Answer 1

please mark it as the brainliest answer

Answer 2

The value of k would be 2 for the given equation.

Given equation is (3k+2)x³ + (k-1)

And the given factor of the equation is 2x+1

If an equation P(x) can be written in the form : (x-a)(x-b)(x-c).....(x-n), then its zeroes are a,b,c,.......n

We can write 2x+1 as 2(x-(-1/2))

So, -1/2 will be a factor of the given equation.

Substituting the value and equating to zero.

(3k+2) (-1/2)³ + (k-1) = 0

= -(3k+2)/8 +(k-1) = 0

= -(3k+2) +8(k-1) = 0

-3k-2+8k -8 = 0

5k - 10 = 0

k =2