Math, asked by joseph2005, 10 months ago

If 2x^2+kx-10 is divisible by x-2, what is the value of k?

Answers

Answered by nikhildalal0607
0

Answer:

place the value of x=2 in the equation

Step-by-step explanation:

then put the equation =0 and only k will be left.

Due to shortage of time I am not giving answer but only telling the way

and you will get your answer

Answered by pnvisinigiri
1

Answer:

k=1

Step-by-step explanation:

given, 2x^2+kx-10 is divisible by x-2,

x-2 is a factor

then

x=2

p(x)=2x^2+kx-10

p(2)=2(2)^2-k(2)-10

0= 2(4)-2k-10

8-2k-10=0

-2+2k=0

2k=2

k=1

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