Question

If (2x+3)(2x+a)=4x2+8x+3 then the value of a is​

Answer 1

(2x + 3) ( 2x + a) = 4x^2 + 8x + 3

now ,

4x^2 + 8x + 3

4x^2 + 2x + 6x + 3

2x ( 2x +1) + 3 (2x +1)

(2x + 1) ( 2x + 3)

now comparing both LHS and RHS

(2 x + 3 ) (2x + a) = (2x +3) (2x + 1)

so,

a= 1.

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Answer 2

Answer: a= 1

Step-by-step explanation:

(2x + 3) (2x + a) = 4x^2 + 8x + 3

Step 1 - multiply both the bracket

(4x^2 + 2ax + 6x + 3a) = 4x^2 + 8x + 3  

Now both side has 4x^2 so its cancel

Remaining    2ax + 6x +3a = 8x + 3

Step 2- Comparing Both side

                       2ax + 3a = 8x - 6x + 3

        now take a common a (2x+ 3) = (2x+3)

            Comparing both side

Therefore the value of a is 1