If (2x+3)(2x+a)=4x2+8x+3 then the value of a is
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(2x + 3) ( 2x + a) = 4x^2 + 8x + 3
now ,
4x^2 + 8x + 3
4x^2 + 2x + 6x + 3
2x ( 2x +1) + 3 (2x +1)
(2x + 1) ( 2x + 3)
now comparing both LHS and RHS
(2 x + 3 ) (2x + a) = (2x +3) (2x + 1)
so,
a= 1.
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Answered by
2
Answer: a= 1
Step-by-step explanation:
(2x + 3) (2x + a) = 4x^2 + 8x + 3
Step 1 - multiply both the bracket
(4x^2 + 2ax + 6x + 3a) = 4x^2 + 8x + 3
Now both side has 4x^2 so its cancel
Remaining 2ax + 6x +3a = 8x + 3
Step 2- Comparing Both side
2ax + 3a = 8x - 6x + 3
now take a common a (2x+ 3) = (2x+3)
Comparing both side
Therefore the value of a is 1
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