If (2x-3,k+2) lies on the graph of equation 2x +3y+15 =0 , Find the value of k
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Since the point lies on the graph, it must satisfy the equation.
So, 2(2k-3) + 3(k+2) + 15 = 0
4k - 6 + 3k + 6 + 15 = 0
7k = -15
k = -15/7
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