if 2x^3+px^2 +q x-2 has a factor [x+2] and leaves remainder7 when divided by [2x-3] find the value of p and q
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Step-by-step explanation:
Let P(x) = 2x3 + ax2 + bx – 2
when P(x) is divided by 2x – 3
P(3/2) = 2(3/2)3 + a(3/2)2 + b(3/2) – 2 = 7
= 27/4 + 9/4a + 3/2b – 2 = 7
= 27 + 9a + 6b – 8/4 = 7
= 9a + 6b = 28 + 8 – 27
= 9a + 6b = 9
⇒ 3a + 2b = 3 ….(1)
Similarly when P(x) is divided by x + 2
x = - 2
2(- 2)3 + a(- 2)2 + b(- 2) – 2 = 0
-16 + 4a – 2b – 2 = 0
⇒ 4a – 2b = 18 ….(2)
On solving equation (1) and (2)
On substituting value of a in equation (1)
3 3 + 2b = 3
2b = 3 – 9
b = -6/2 = - 3
b = - 3
a = 3, b = - 3
On substituting value of a and b
2x3 + 3a2 – 3x – 2
When x + 2 is factor
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