If 2x - 3 Y = 10 and x y is equals to 16 find the value of 8 x cube -27 y cube
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Identity used
a³- b³ = (a - b)(a²+ab+b²)
= (a - b)³ + 3ab(a-b)
Therefore, 8x³ - 27y³ = (10)³ +3(16)(10)
= 100+480
= 580
a³- b³ = (a - b)(a²+ab+b²)
= (a - b)³ + 3ab(a-b)
Therefore, 8x³ - 27y³ = (10)³ +3(16)(10)
= 100+480
= 580
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