if 2x-3is factors of 6x^2+x+a find the value of a
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REMAINDER THEORM
P(X) = 2x-3
P(0) = 2x-3 = 0
= 2x = 0+3
= 2x = 3
x = 3/2
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next step:
p(0) = 6*(3/2)²+3/2+a = 0
6*9/4+3/2+a = 0 ( 6*9/4 = 54/4 = 27/2 )
27/2+3/2+a = 0
30/2+a = 0
15+a = 0
a = 0-15
a= -15
saijuchacko:
hope it helps mate!!!!
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