What is the distance in (km) of a quasar from which light taken 3 x 109 years to reach the earth? The speed oflight c = 3 x 10 8 m/s.
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Answer:
The total time in seconds :
t = 3×109×365×24×3600
= 10,312,272,000 sec
speed = 3 × 10^5 Km/s
So distance covered is :
d = speed × time
= 3 × 10^5 × 10,312,272,000
= 3.09 × 10^15 Km
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