if 2x-3y= 10 and xy = 16 ;find the value of 8x^3-27y^3
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Answered by
122
Hey !!
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( 2 x - 3 y ) 3 = ( 2x )3 - ( 3y)3 - 3 ( 2x × 3y ) ( 2x - 3y)
(10)3 = 8x3 - 27y3 - 3 (6xy) (10)
1000 = 8x3 - 27y3 - 3 (96)(10)
1000 = 8x3 - 27y3 - 2880
8x3 -27y3 = 2880+1000= 3880
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( 2 x - 3 y ) 3 = ( 2x )3 - ( 3y)3 - 3 ( 2x × 3y ) ( 2x - 3y)
(10)3 = 8x3 - 27y3 - 3 (6xy) (10)
1000 = 8x3 - 27y3 - 3 (96)(10)
1000 = 8x3 - 27y3 - 2880
8x3 -27y3 = 2880+1000= 3880
Avni511:
sorry wrong ans
answer is 3880
Ok let me see !!
ok
tell me fast
Hmm done !
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Hey is your answer
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