If 2x-3y=10 and xy=16;find the value of
8x^3-27y^3
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7
Answer:
2x - 3y = 10
On Cubing both sides -
(2x - 3y)³ = (10)³
⇒ (2x)³ - (3y)³ - 3 * 2x * 3y ( 2x - 3y) = 1000
⇒ 8x³ - 27y³ - 18 xy ( 10 ) = 1000
⇒ 8x³ - 27y³ - 18 * 16 * 10 = 1000
⇒ 8x³ - 27y³ - 2880 = 1000
⇒ 8x³ - 27y³ = 1000 + 2880
⇒ 8x³ - 27y³ = 3880
Hence, the answer is 3880.
happy303:
so
3 × 16 ( 10 ) thats it
i guess ur answer is wrong
3ab = 3 * 2x * 3y = 18xy
The answer is absolutely correct!
Please be sure before reporting the answer. It was correct.
already ab is given as 16
xy is given 16, but a = 2x and b = 3y
(a-b)³ = a³ - b³ - 3ab(a-b)
In place of a, you have to put 2x and in place of b, you have to put 3y
Answered by
0
hey the answer is. ....
hope it helps uu frnd.
hope it helps uu frnd.
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