if 2x+3y=10,xy=5, find the value of 4x²+9y²
Answers
Answered by
11
Gicven,
2x+3y=10,xy=5
∴ (2x+3y)²=10²
4x² + 9y² +12xy=100
4x² + 9y² +12x5=100
4x² + 9y² =40
2x+3y=10,xy=5
∴ (2x+3y)²=10²
4x² + 9y² +12xy=100
4x² + 9y² +12x5=100
4x² + 9y² =40
Answered by
3
(2x+3y)*whole square =(10)*whole square
4x*square+9y*square+2×2x×3y=100
4x*square+9y*square+12xy=100
4x*square+9y*square+12×5=100
4x*square+9y*square+60=100
4x*square+9y*square=100-60
ans will be
4x*square+9y*square=40
4x*square+9y*square+2×2x×3y=100
4x*square+9y*square+12xy=100
4x*square+9y*square+12×5=100
4x*square+9y*square+60=100
4x*square+9y*square=100-60
ans will be
4x*square+9y*square=40
Similar questions