If 2x+3y=12 and xy=16. Find the values of 8x^3-27y^3
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2
Answer:
2x+3y=12
cube on both sides,
(2x+3y)^3 =12^2
by the identity (a+b)^3= a^3 +b^3 +3ab(a+b)
here, 8x^3 + 27y^3 +3(6xy)(2x+3y) =12^3
putting the values which are given ,
8x^3 +27y^3 +18(6)(12) = 1728
8x^3 + 27y^3 +1296 = 1728
8x^3 +27y^3 = 1728-1296
8x^3 +27y^3 =432
so,432 is the correct answer
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hope it helps plz mark as brainlist
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Answer:
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sorry i don`t know the answer
if equation is 2x-3y i would solve it
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