Question

If 2x+3y=12 and xy=16. Find the values of 8x^3-27y^3​

Answer 1

Answer:

2x+3y=12

cube on both sides,

(2x+3y)^3 =12^2

by the identity (a+b)^3= a^3 +b^3 +3ab(a+b)

here, 8x^3 + 27y^3 +3(6xy)(2x+3y) =12^3

putting the values which are given ,

8x^3 +27y^3 +18(6)(12) = 1728

8x^3 + 27y^3 +1296 = 1728

8x^3 +27y^3 = 1728-1296

8x^3 +27y^3 =432

so,432 is the correct answer

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

sorry i don`t know the answer

if equation is 2x-3y i would solve it