If 2x + 3y = 12 and xy = 6, find the value of 4x^2 +9y^2
Answers
Answered by
7
Answer:
Given:
2x + 3y = 12
xy = 6
To Find:
4x² + 9y²
Solution:
2x + 3y = 12
(2x + 3y)² = 144
4x² + 9y² + 12xy = 144
4x² + 9y² = 144 - 12xy
4x² + 9y² = 144 - (12×6)
4x² + 9y² = 144 - 72
4x² + 9y² = 72
Answered by
2
Answer:
4x^2+9y^2=72
Step-by-step explanation:
2x+3y=12 xy=6
(2x+3y)^2=(2x)^2+(3y)^2+2(2x)(3y)
(12)^2=4x^2+9y^2+12xy
144=4x^2+9y^2+12(6)
144-72=4x^2+9y^2
4x^2+9y^2=72
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