Math, asked by aayushgautam226, 3 months ago

If 2x + 3y = 12 and xy = 6, find the value of 4x^2 +9y^2​

Answers

Answered by raghavgoyal215
7

Answer:

Given:

2x + 3y = 12

xy = 6

To Find:

4x² + 9y²

Solution:

2x + 3y = 12

(2x + 3y)² = 144

4x² + 9y² + 12xy = 144

4x² + 9y² = 144 - 12xy

4x² + 9y² = 144 - (12×6)

4x² + 9y² = 144 - 72

4x² + 9y² = 72

Answered by vathsalyathadasari
2

Answer:

4x^2+9y^2=72

Step-by-step explanation:

2x+3y=12 xy=6

(2x+3y)^2=(2x)^2+(3y)^2+2(2x)(3y)

(12)^2=4x^2+9y^2+12xy

144=4x^2+9y^2+12(6)

144-72=4x^2+9y^2

4x^2+9y^2=72

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