Math, asked by anushkasingh2440, 1 year ago

If 2x+3y=12 and xy =6 , find the value of 8x^5 - 27 y^3


Mohit77777777: Wrong question
anushkasingh2440: No it's Not wrong

Answers

Answered by kamini87
3

2x+3y=12

Xy=6

Then,x=3

Y=2

Therefore, 8(3)^5-27(2)^3=8*243-27*8

8*216=1728


anushkasingh2440: Can you give a full solution of it
Similar questions