Question

if 2x = 3y = 12 and xy = 6, find the value of 8x³ + 27y³ using substitution method please don't do any spam answers​

Answer 1

Answer:

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Answer 2

2x+3y=12
Xy =6
Find 8x^3+27y^3
2x+3y=12
Cubing both sides
(2x+3y)^3=12^3
(a+b)^3=a^3+b^3+3ab(a+b)=1728
8x^3+27y^3+3×2x×3y(2x+3y)=1728
8x^3+27y^3+18×6×12=1728
8x^3+27y^3+1296=1728
8x^3+27y^3= 432