Math, asked by mohantalinky9127, 11 months ago

If 2X + 3Y=13 &Amp; Xy=6 Find 8X^3 - 27Y^3

Answers

Answered by Siddharta7
2

2x +3y = 13-----(1)

xy =6-----(2)

8x³ +27y³  

= (2x)³ +(3y)³

= (2x+3y)³ - 3*2x*3y(2x+3y)  [using (a+b)³ = a³+b³+3ab(a+b)]

= (13)³- 18 * 6 *13 [ using (1) and (2)]

= 2197 - 1404

=793

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