If 2x+3y=5 and xy=1 then find the value of 8x^3+27^3
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Hey!!!!
Let's solve
=> 2x + 3y = 5
Cube both sides
=> (2x + 3y)³ = 125
=> 8x³ + 27y³ + 3(2)(3)(xy)(2x + 3y) = 125
Replacing all values we have
=> 8x³ + 27y³ + 18(5)(1) = 125
=> 8x³ + 27y³ = 35
Hope this helps
Let's solve
=> 2x + 3y = 5
Cube both sides
=> (2x + 3y)³ = 125
=> 8x³ + 27y³ + 3(2)(3)(xy)(2x + 3y) = 125
Replacing all values we have
=> 8x³ + 27y³ + 18(5)(1) = 125
=> 8x³ + 27y³ = 35
Hope this helps
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