if 2x-3y=7 and (a+b)x-(a+b-3)y=4a+b have infinitely many if 2x-3y=7 and (a+b)x-(a+b-3)y=4a+b have infinitely many solutions,finda,b
Answers
Answer:
2x-3y=7
(a+b)x-(a+b-3)y=4a+b
the equation has infinitely many solutions so
A1/a2 = b1/B2 = c1/c2
2/a+b = -3/a+b-3 = 7/4a+b
by cross multiplication of
A1/a2 = b1/B2
2a + 2b -6 = -3a - 3b
5a + 5b = 6 -------------------1 eq
A1/a2 = c1/c2
8a + 2b. = 7a + 7b
a - 5b = 0 ----------------------2 eq
by elimination method
5a + 5b = 6
5a -25b = 0
-. +. -
30b = 6
b =. 1/5
putting value of b in eq 1
5a + 5(1/5). = 6
5a + 5/5 = 6
5a +. 1 =. 6
5a. =. 6-1
a. = 5/5
a = 1
Answer:
2x-3y=7
(a+b)x-(a+b-3)y=4a+b
the equation has infinitely many solutions so
A1/a2 = b1/B2 = c1/c2
2/a+b = -3/a+b-3 = 7/4a+b
by cross multiplication of
A1/a2 = b1/B2
2a + 2b -6 = -3a - 3b
5a + 5b = 6 -------------------1 eq
A1/a2 = c1/c2
8a + 2b. = 7a + 7b
a - 5b = 0 ----------------------2 eq
by elimination method
5a + 5b = 6
5a -25b = 0
-. +. -
30b = 6
b =. 1/5
putting value of b in eq 1
5a + 5(1/5). = 6
5a + 5/5 = 6
5a +. 1 =. 6
5a. =. 6-1
a. = 5/5
a = 1
Step-by-step explanation: