If 2x+3y=8 and xy=2,then find 8x cube+27y cube
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Given,
2x+3y=8
XY=2
Since,
(A+B)³=a³+b³+3ab(a+B)
:.(2x+3y)³=(2x)³+(2y)³+3(2x)(3y)(2x+3y)
Putting value
8³=8x³+27y³18(2)(8)
512=8x³+27y³+288
512-288=8x³+27y³
224=8x³+27y³
(ÆÑẞWĒR)
#Mærk ãß thē Bråìñlìêßt
Rëgārdß
Tèàm Káñçhâ
2x+3y=8
XY=2
Since,
(A+B)³=a³+b³+3ab(a+B)
:.(2x+3y)³=(2x)³+(2y)³+3(2x)(3y)(2x+3y)
Putting value
8³=8x³+27y³18(2)(8)
512=8x³+27y³+288
512-288=8x³+27y³
224=8x³+27y³
(ÆÑẞWĒR)
#Mærk ãß thē Bråìñlìêßt
Rëgārdß
Tèàm Káñçhâ
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