Question

. If [2x 4] [x/-8]=0 find the positive value of x​

Answer 1

Answer:

$\left(2x\cdot \:4\right)\left(\frac{x}{-8}\right)=0\quad :\quad x=0$

Step-by-step explanation:

$\left(2x\cdot \:4\right)\left(\frac{x}{-8}\right)=0$

$\mathrm{Simplify}$

$-x^2=0$

$\mathrm{Divide\:both\:sides\:by\:}-1$

$\frac{-x^2}{-1}=\frac{0}{-1}$

$\mathrm{Simplify}$

$x^2=0$

$\mathrm{Apply\:rule}\:x^n=0\quad \Rightarrow \quad \:x=0$

$x=0$

Answer 2

Step-by-step explanation:

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