if 2x=4y=8z and 1/2x+1/4y+1/6z=4 find the value of x
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Answer:
7/48
given 2x=4y=8z
2x=4y (x=2y) & 4y=8z (y=2z) & 2x=8z (x=4z)
given equation is
1/2x+1/4y+1/6z=24/7
( 1/2×(4z))+(1/4×(2z))+(1/6×z)=24/7
(1/8z)+(1/8z)+(1/6z)=24/7
((6+6+8)/48z)=24/7
20/48z = 24/7
z = (20×7)/(48×24)
z=140/1152
z=35/2887/48
given 2x=4y=8z
2x=4y (x=2y) & 4y=8z (y=2z) & 2x=8z (x=4z)
given equation is
1/2x+1/4y+1/6z=24/7
( 1/2×(4z))+(1/4×(2z))+(1/6×z)=24/7
(1/8z)+(1/8z)+(1/6z)=24/7
((6+6+8)/48z)=24/7
20/48z = 24/7
z = (20×7)/(48×24)
z=140/1152
z=35/288
Step-by-step explanation:
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