Question

If 2x = 4y = 8z and 1/2x+1/4y+1/8z= 4 find the value of x.​

Answer 1

Answer:

x = $\frac{128}{21}$ pls mark me brainliest.

Step-by-step explanation:

2x = 4y = 8z  [Given]

2x = 8z

x = 4z

4y = 8z

y = 2z

$\frac{1}{2} x + \frac{1}{4} y + \frac{1}{8} z = 4$

Brainly is showing error so I am not using fraction properly

(1/2)4z + (1/4)2z + (1/8)z = 4

2z + z/2 + z/8 = 4

(16z + 4z + z)/8 = 4

21z/8 = 4

21z = 32

z = $\frac{32}{21}$

x = 4z

x = 4 × $\frac{32}{21}$

x = 128/21

Answer 2

Answer is given in attached picture.

Hope it helps you!