what extra force should an engine of a car develop such that its velocity changes from 5m/s to 25m/s over a distance of 10m ,when the mass of the car is 900kg?
i need it step by step please
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Answer:
27000N
Explanation:
F=m*a
m=900kg
v² = u² + 2as
v=25m/s
u=5m/s
s=10m
625=25+2*a*10
626-25=20a
600/20=a
a=30
F=ma
=900*30
=27000N
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