Question

if 2X + 6Y=8 and X + KY=10 are the pairs of linear equations having their lines parallel to each other then the value of k is
​

Answer 1

Answer:

2x−ky+3=04x+6y−5=0

To represent parallel lines,

4

2

=

6

−k

⟹

2

1

=

6

−k

⟹−k=

2

6

=−3

∴k=−3