Question

If 2x+ky=10k, intersects x-axis at (2,0), find k.

Answer 1

Hii friend...............
2x+ky = 10k
putting x= 2 and y = 0
2(2) + k(0) = 10k
4 + 0 = 10k
4/ 10 = k
2/5 = k

So , The value of k is 2/5.....
Thankss
Hope my answer is right ☆☆☆

Answer 2

This is the required value of K = 2/5