Question

if 2x+y=8 find 4x²+y²​

Answer 1

2x+y=8

(2x+y)^2=(8)^2

4x^2 +y^2+4xy=64

so 4x^2 +Y^2=64-4xy

Answer 2

2x+y=8

X=8-y/2

4x^2+y^2

4(8-y/2) ^2+y^2

4(64-y^2/4) +y^2

64