Question

If 2x2+2\x2=79. Find the value of x-1\x​

Answer 1

Step-by-step explanation:

$2 {x}^{2} + \frac{2}{ {x}^{2} } = 79 \\ {x}^{2} + \frac{1}{ {x}^{2} } = \frac{79}{2} \\ now \\ {(x - \frac{1}{x} )}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } - 2 \\ {(x - \frac{1}{x} )}^{2} = \frac{79}{2} - 2 \\ = \frac{75}{2} \\ {(x - \frac{1}{x} )} = \sqrt{ \frac{75}{2} }$