If 2y= X(1+dy/dx) show that y2 is constant
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Answer:
y''=2C
Step-by-step explanation:
The equation can be expressed as dy/dx - (2/x)y=-1 and this has an integrating
factor e^(integral -2/x dx) =e^(-2ln(*x)=1/x^2 and multiplying the DE by this gives
((1/x^2)y)'= -1/x^2 and integrating gives (1/x^2)y=1/x + C giving
y=x+Cx^2 and y'=1+2Cx and y"=2C which is a constant.
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